## Algebra 2 Common Core

We substitute the value in. We have $\frac{5}{3}(3(5)-6)-(6-4(5))$. Simplifying the multiplication in the parentheses gives us $\frac{5}{3}(15-6)-(6-20)$. Now, we simplify the subtraction in the parentheses, giving us $\frac{5}{3}(9)-(-14)=15+14=29$.