Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 46: 49

Answer

The solution is $x=$ $\dfrac{11}{8}$.

Work Step by Step

You are given the equation $2|3x-7|=10x-8$. Divide both sides by $2$: $2|3x-7|=10x-8$ $|3x-7|=$ $\dfrac{10x-8}{2}$ $|3x-7|=5x-4$ Separate into two equations: $3x-7=5x-4$ $or$ $3x-7=-(5x-4)$ Solve: $3x-7=5x-4$ $-7=2x-4$ $-3=2x$ $x=-$ $\dfrac{3}{2}$ Second equation: $3x-7=-(5x-4)$ $3x-7=-5x-4$ $8x-7=4$ $8x=11$ $x=$$\dfrac{11}{8}$ The solution is $x=$ $\dfrac{11}{8}$ and $x=-$ $\dfrac{3}{2}$ is an extraneous solution.
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