Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 46: 13

Answer

$x=-\dfrac{5}{3}\text{ OR }x=3$

Work Step by Step

Using the properties of equality, the given equation, $ 2|3x-2|=14 ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{2|3x-2|}{2}=\dfrac{14}{2} \\\\ |3x-2|=7 .\end{array} Since for any $c\gt0$, $|x|=c$ implies $x=c \text{ or } x=-c,$ the equation above is equivalent to \begin{array}{l}\require{cancel} 3x-2=7 \\\\\text{OR}\\\\ 3x-2=-7 .\end{array} Solving each equation results to \begin{array}{l}\require{cancel} 3x-2+2=7+2 \\ 3x=9 \\ \dfrac{3x}{3}=\dfrac{9}{3} \\ x=3 \\\\\text{OR}\\\\ 3x-2+2=-7+2 \\ 3x=-5 \\ \dfrac{3x}{3}=-\dfrac{5}{3} \\ x=-\dfrac{5}{3} .\end{array} Hence, $ x=-\dfrac{5}{3}\text{ OR }x=3 .$
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