## Algebra 2 Common Core

$$x \ge -4 \text{ or } x \le -8$$ Refer to the graph below.
Solve each inequality: \begin{align*} 8x &\gt -32\\\\ \frac{8x}{8} &\gt \frac{-32}{8}\\\\ x &\ge -4 \end{align*} $$\text{or}$$ \begin{align*} -6x&\ge 48\\\ \frac{-6x}{-6} &\le \frac{48}{-6}& \text{(Dividing by a negative number changes the inequality symbol)}\\\\ x&\le -8 \end{align*} Graph each inequality to obtain the one in the attached image above. Since the compound inequality involves the conjunction $\text{OR}$, then the solutions to the inequality are the combined numbers of the two graphs.