## Algebra 2 Common Core

$-4 \le x \le 2$ Refer to the graph below.
Solve each inequality: \begin{align*} 3x &\ge -12\\\\ \frac{3x}{3} &\ge \frac{-12}{3}\\\\ x &\ge -4 \end{align*} $$\text{and}$$ \begin{align*} 8x&\le 16\\\\ \frac{8x}{8} &\le \frac{16}{8}\\\\ x&\le 2 \end{align*} Graph each inequality to obtain the one in the attached image below. Since the compound inequality involves the conjunction $\text{AND}$, then the solutions to the inequality are numbers common to both graphs, which are the numbers in the interval $-4 \le x \le 2$.