## Algebra 2 Common Core

$k=-\frac{1}{6}h-\frac{7}{3}$
We start by adding 2k to both sides. That gives us $6k+h=-14$. Now, we subtract h from both sides to isolate k with its coefficient, which gives us $6k=-h-14$. Finally, we divide both sides by 6 to fully isolate k. $\frac{6k}{6}=\frac{-h-14}{6}$ equals $k=-\frac{1}{6}h-\frac{7}{3}$