Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-4 Solving Equations - Lesson Check: 5

Answer

$k=\frac{1}{3}z+2$

Work Step by Step

First, we add 2z to both sides to isolate k with its coefficient. We have $6k-2z=12$ is $6k=2z+12$. Now, we divide both sides by 6 to fully isolate k. We have $\frac{6k}{6}=\frac{2z+12}{6}$ is $k=\frac{1}{3}z+2$
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