Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Prerequisite Skills - Page 612: 9


$x= 4 \pm \sqrt{31} $

Work Step by Step

To complete the square, we add $(b/2)^2$ to both sides and subtract the constant. Adding $4^2 =16$ and adding 15, each to both sides. $x^2 - 8x +16 = 31$ $(x-4)^2 = 31$ $x= 4 \pm \sqrt{31} $
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