Answer
$x= 4 \pm \sqrt{31} $
Work Step by Step
To complete the square, we add $(b/2)^2$ to both sides and subtract the constant.
Adding $4^2 =16$ and adding 15, each to both sides.
$x^2 - 8x +16 = 31$
$(x-4)^2 = 31$
$x= 4 \pm \sqrt{31} $
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - Prerequisite Skills - Page 612: 9
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