Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Prerequisite Skills - Page 612: 8

Answer

No real solution

Work Step by Step

To complete the square, we add $(b/2)^2$ to both sides and subtract the constant. $(-4/2)^2 = 4$ $x^2 -4x + 4 = -3$ A square cannot be negative, so this has no real solution
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