Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 670: 18


$$ x^2+y^2=106$$

Work Step by Step

Since the center is at the origin, we use the distance formula to find that the radius must be: $$\sqrt{\left(5-0\right)^2+\left(9-0\right)^2}=\sqrt{106}$$ Thus, it follows: $$x^2+y^2=r^2 $$ $$ x^2+y^2=106$$
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