Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Chapter Review - Page 670: 13

Answer

$x^2=12y$

Work Step by Step

If the parabola has its vertex at $(0,0)$ and its focus at $(0,p)$ then the equation is: $x^2=4py$. Hence here $p=3$, thus the equation is: $x^2=12y$
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