Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.7 Solve Quadratic Systems - 9.7 Exercises - Skill Practice - Page 662: 31



Work Step by Step

Adding the first and negative nine times the second equation we get: $-32x^2-56x+576=-160\\4x^2+7x-92=0\\(x-4)(4x+23)=0$ Thus $x=4$ or $x=-5.75$ Plugging this into the second equation we get: if $x=4$: $64-y^2-64=0\\y=0$ Using the quadratic formula $y=8\pm4\sqrt{21}$ if $x=-5.75$: $132.25+y^2-64=0\\y^2=-68.25$ Thus here there isn't any solution. Thus the solutions are: $(4,0)$
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