## Algebra 2 (1st Edition)

$(2,0.4),(-2,0.2)$
Substituting the first equation into the second one we get: $10y-6=-2\\10y=4\\y=0.4$ If $y=0.4$, then $x^2=4$, thus $x=\pm2$. Thus the solutions are: $(2,0.4),(-2,0.2)$