Chapter 9 Quadratic Relations and Conic Sections - 9.4 Graph and Write Equations of Ellipses - Guided Practice for Examples 2, 3, and 4 - Page 636: 5

$$\frac{x^2}{36}+\frac{y^2}{25}=1$$

We know the following equation for an ellipse centered at the origin: $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$ Where $(a,0)$ is the vertex and $(b,0)$ is the co-vertex. Thus, we find: $$\frac{x^2}{(6)^2}+\frac{y^2}{(-5)^2}=1$$ $$\frac{x^2}{36}+\frac{y^2}{25}=1$$