Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.4 Graph and Write Equations of Ellipses - Guided Practice for Examples 2, 3, and 4 - Page 636: 4

Answer

$$\frac{x^2}{49}+\frac{y^2}{4}=1$$

Work Step by Step

We know the following equation for an ellipse centered at the origin: $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$ Where $(a,0)$ is the vertex and $(b,0)$ is the co-vertex. Thus, we find: $$\frac{x^2}{(7)^2}+\frac{y^2}{(2)^2}=1$$ $$\frac{x^2}{49}+\frac{y^2}{4}=1$$
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