Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.4 Graph and Write Equations of Ellipses - 9.4 Exercises - Skill Practice - Page 637: 21

Answer

$$\frac{y^2}{144}+\frac{x^2}{121}=1$$

Work Step by Step

We know the following equation for an ellipse centered at the origin: $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$ Where $(a,0)$ is the vertex and $(b,0)$ is the co-vertex. Thus, we find: $$\frac{y^2}{(12)^2}+\frac{x^2}{(11)^2}=1$$ $$\frac{y^2}{144}+\frac{x^2}{121}=1$$
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