## Algebra 2 (1st Edition)

$$\frac{y^2}{36}+\frac{x^2}{16}=1$$
We know the following equation for an ellipse centered at the origin: $$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$ Where $(a,0)$ is the vertex and $(b,0)$ is the co-vertex. Thus, we find: $$\frac{y^2}{(-6)^2}+\frac{x^2}{(4)^2}=1$$ $$\frac{y^2}{36}+\frac{x^2}{16}=1$$