Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Skill Practice - Page 617: 30

Answer

isosceles

Work Step by Step

The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here: $a=\sqrt{(3-6)^2+(5-9)^2}=\sqrt{25}=5$, $b=\sqrt{(3-11)^2+(5-9)^2}=\sqrt{80}$, $c=\sqrt{(6-11)^2+(9-9)^2}=\sqrt{25}=5$, thus the triangle is isosceles.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.