Chapter 9 Quadratic Relations and Conic Sections - 9.1 Apply the Distance and Midpoint Formulas - 9.1 Exercises - Skill Practice - Page 617: 3

$$\left(4,\:\frac{15}{2}\right)$$

Using the distance formula, we find: $$\sqrt{\left(8-0\right)^2+\left(15-0\right)^2}\\ 17$$ Using the midpoint formula, we find: $$\left(\frac{8+0}{2},\:\frac{15+0}{2}\right)\\ \left(4,\:\frac{15}{2}\right)$$