## Algebra 2 (1st Edition)

$$\frac{4}{5}$$
We first recall that dividing is the same as multiplying by the inverse. Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find: $$\frac{4x}{5x-20}\div \frac{\left(x^2-2x\right)}{x^2-6x+8} \\ \frac{4x\left(x-4\right)}{\left(5x-20\right)x} \\ \frac{4x\left(x-4\right)}{\left(5x-20\right)x} \\ \frac{4\left(x-4\right)}{5\left(x-4\right)} \\ \frac{4}{5}$$