Answer
$$\frac{x+5}{x-1}$$
Work Step by Step
Using the rules of exponents and cancelling common factors in the numerator and the denominator, we find:
$$\frac{\left(x+5\right)\left(x^2+x+1\right)}{x^3-1}\\ \frac{\left(x+5\right)\left(x^2+x+1\right)}{\left(x-1\right)\left(x^2+x+1\right)} \\ \frac{x+5}{x-1}$$
