## Algebra 2 (1st Edition)

From earlier parts we have: $P=\frac{aWD^2}{L}$. Hence if all dimensions are doubled, then $P'=\frac{a(2W)(2D)^2}{(2L)}=\frac{a2W4D^2}{2L}=\frac{4aWD^2}{L}=4P$. Thus $P$ becomes 4 times as much as it was.