## Algebra 2 (1st Edition)

$6.674 \times 10^{-11} N m^2 /kg^2$
From the previous part (a), we have $F= G\dfrac{m_1m_2}{d^2}$ Re-arrange as: $G=\dfrac{Fd^2}{m_1m_2}$ Plugging in the data, we have $G=\dfrac{(3.53 \times 10^{22}) (1.5 \times 10^{11})^2}{1.99 \times 10^{30} (5.98 \times 10^{24})} \approx 6.674 \times 10^{-11} N m^2 /kg^2$