## Algebra 2 (1st Edition)

$L(I)=10\log\frac{I}{I_0}$ where $I_0=10^{−12}$. Hence here $L(I)_{whale}=10\log\frac{10^{6.8}}{10^{−12}}=10\log{10^{18.8}}=10\cdot18.8=188$ $L(I)_{human}=10\log\frac{10^{0.8}}{10^{−12}}=10\log{10^{12.8}}=10\cdot12.8=128$ Thus the whale can make a louder sound by $60$ decibels.