Answer
$\approx76.2$
Work Step by Step
$L(I)=10\log\frac{I}{I_0}$ where $I_0=10^{−12}$. The three conversations have a combined intensity of $I=3\cdot1.4\cdot10^{-5}=4.2\cdot10^{-5}$
Hence here $L(I)=10\log\frac{4.2\cdot10^{-5}}{10^{−12}}=10\log{4.2\cdot10^7}\approx76.2$