Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Problem Solving - Page 484: 39c



Work Step by Step

From part a), the model for the population is: $y=494290(1.03)^x$ Hence here our equation is: $590000=494290(1.03)^x\\\frac{590000}{494290}=1.03^x\\x=\log_{1.03}{\frac{590000}{494290}}\approx6$ Hence the answer is: $1990+6=1996$
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