## Algebra 2 (1st Edition)

$1996$
From part a), the model for the population is: $y=494290(1.03)^x$ Hence here our equation is: $590000=494290(1.03)^x\\\frac{590000}{494290}=1.03^x\\x=\log_{1.03}{\frac{590000}{494290}}\approx6$ Hence the answer is: $1990+6=1996$