Answer
$494290(1.03)^x$
Work Step by Step
Let $x$ be the number of years after $1990$. Then our initial amount is $494290$,and the percent increase is: $0.03$. Then the number of parakeets is ($0\leq x\leq10$): $494290(1+0.03)^x=494290(1.03)^x$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Problem Solving - Page 484: 39a
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