Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 7 Exponential and Logarithmic Functions - 7.1 Graph Exponential Growth Functions - 7.1 Exercises - Problem Solving - Page 484: 39a



Work Step by Step

Let $x$ be the number of years after $1990$. Then our initial amount is $494290$,and the percent increase is: $0.03$. Then the number of parakeets is ($0\leq x\leq10$): $494290(1+0.03)^x=494290(1.03)^x$
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