Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - Chapter Test - Page 469: 37c

Answer

No.

Work Step by Step

Let $E=625s_1^2$. If $2E=625s_2^2$, then if we divide the second equation by the first one, we get: $2=\frac{s_2^2}{s_1^2}\\\sqrt2=\frac{s_2}{s_1}$ Thus the statement is false.
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