## Algebra 2 (1st Edition)

$$2^{\frac{7}{5}}$$
Using the rules of radicals to simplify, we find: $$\sqrt[5]{2^4}\sqrt[5]{8} \\ 2^{\frac{4}{5}}\sqrt[5]{2^3}\\ 2^{\frac{4}{5}}\cdot \:2^{\frac{3}{5}}\\ 2^{\frac{7}{5}}$$