#### Answer

$$2^{\frac{7}{5}}$$

#### Work Step by Step

Using the rules of radicals to simplify, we find:
$$\sqrt[5]{2^4}\sqrt[5]{8} \\ 2^{\frac{4}{5}}\sqrt[5]{2^3}\\ 2^{\frac{4}{5}}\cdot \:2^{\frac{3}{5}}\\ 2^{\frac{7}{5}}$$

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Published by
McDougal Littell

ISBN 10:
0618595414

ISBN 13:
978-0-61859-541-9

$$2^{\frac{7}{5}}$$

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