Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Skill Practice - Page 443: 32

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Given: $f(x)=-6x^2$ Since the vertex form is $y=a(x-h)^2+k$, we know: $a=-6\\h=0\\k=0$ The vertex then will be $(h,k)=(0,0)$ Find some values: $x=1 \rightarrow y=-6\\x=2 \rightarrow y=-24\\x=3 \rightarrow y=-54$