Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 6 Rational Exponents and Radical Functions - 6.4 Use Inverse Functions - 6.4 Exercises - Skill Practice - Page 443: 21

Answer

Answer B

Work Step by Step

We can see the graph of a line passes through two points $(0,-4)$ and $(3,-2)$ Obtain: $y-y_1=\frac{y_1-y_2}{x_1-x_2}(x-x_1)\\ y-(-4)=\frac{-4-(-2)}{0-3}(x-0)\\y+4=\frac{-2}{-3}(x)\\ y+4=\frac{2}{3}x\\y=\frac{2}{3}x-4$ Find the inverse of the above equation: $y=\frac{2}{3}x-4\\x=\frac{2}{3}y-4\\x+4=\frac{2}{3}y\\\frac{3}{2}(x+4)=(\frac{2}{3}y)\frac{3}{2}\\\frac{3}{2}(x+4)=y\\\frac{3}{2}x+6=y\\y=\frac{3}{2}x+6$ Hence, the correct answer is B.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.