## Algebra 2 (1st Edition)

In the given polynomial of degree $5$, there are $5$ zeros. By Descartes' Rule, we can notice form the graph that the function has one x-intercept, and the graph crosses the x-axis in both cases. This means that we have $1$ real zero which lies on the left side of the origin, so the zero is negative. Hence, Negative real zeros= 1 Imaginary zeros = 4