## Algebra 2 (1st Edition)

In the given polynomial of degree $3$, there are $3$ zeros. By Descartes' Rule, we can notice form the graph that the function has $2$ Negative real zeros (approximately -1 and -2.8) and $1$ Positive real zero (approximately 1.8). Hence, Positive real zeros = 1 Negative real zeros= 2 Imaginary zeros = 0