Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.7 Apply the Fundamental Theorem of Algebra - 5.7 Exercises - Skill Practice - Page 385: 53

Answer

Positive real zeros = 1 Negative real zeros= 2 Imaginary zeros = 0

Work Step by Step

In the given polynomial of degree $3$, there are $3$ zeros. By Descartes' Rule, we can notice form the graph that the function has $2$ Negative real zeros (approximately -1 and -2.8) and $1$ Positive real zero (approximately 1.8). Hence, Positive real zeros = 1 Negative real zeros= 2 Imaginary zeros = 0
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