## Algebra 2 (1st Edition)

$2$ million.
We use the fact that $x=3$ is a solution (i.e. by the factor theorem $x-3$ is a factor). Our equation is: $48=-4x^3+12x^2+16x\\0=-4x^3+12x^2+16x-48=(x-3)\cdot-4(x^2-4)=-(x+2)(x-2)(x-3)$ We know that $x\gt0$ and $x\ne3$, thus $x=2$.