Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.5 Apply the Remainder and Factor Theorems - 5.5 Exercises - Problem Solving - Page 367: 41


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Work Step by Step

Our equation is: $4=-x^3+4x^2+x\\0=-x^3+4x^2+x-4=(x-4)\cdot-(x^2-1)=-(x+1)(x-1)(x-4)$ We know that $x\gt0$ and $x\ne4$, thus $x=1$.
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