Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - Chapter Test - Page 323: 31


See below.

Work Step by Step

Using the Pythagorean Theorem and the fact that $x$ is non-negative we get: $(9x)^2+(16x)^2=32^2\\81x^2+256x^2=1024\\337x^2=1024\\x^2=\frac{1024}{337}\\x=\sqrt{\frac{1024}{337}}$ Hence the height: $9x=9\sqrt{\frac{1024}{337}}\approx15.69$ in and the width is: $16x=16\sqrt{\frac{1024}{337}}\approx27.89$ in
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