# Chapter 4 Quadratic Functions and Factoring - Chapter Test - Page 323: 24

$$x=\frac{-1\pm 2\sqrt{6}i}{5}$$

#### Work Step by Step

We first check that the function is in the form $ax^2+bx+c$. Then, using the quadratic formula, we obtain: $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$$ $$x=\frac{-2\pm \sqrt{(2)^2-4(5)(5)}}{2(5)}$$ $$x=\frac{-1\pm 2\sqrt{6}i}{5}$$

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