Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.8 Use the Quadratic Formula and the Discriminant - 4.8 Exercises - Skill Practice - Page 297: 63

Answer

$$(x+4)(x-3) \\ x^2-3x+4x-12 \\ x^2+x-12$$

Work Step by Step

We start with the factored form of the equation that would make these solutions, and then we use the FOIL method to get the equation into the form $ax^2+bx+c$. Thus, we obtain: $$(x+4)(x-3) \\ x^2-3x+4x-12 \\ x^2+x-12$$
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