Answer
$2$ solutions if $8\gt c$, one solution if $8=c$, and no solution if $8\lt x$.
Work Step by Step
The discriminant is $D=b^2-4ac$. If $D\gt0$ we have $2$, if $D=0$ we have one, and if $D\lt0$ we have no solution.
Hence here $D=64-4c$. $64-4c\gt0\\64\gt4c\\16\gt c.$
$64-4c=0\\64=4c\\8= c.$
$64-4c\lt0\\64\lt4c\\8\lt c.$
Thus we have $2$ solutions if $8\gt c$, one solution if $8=c$, and no solution if $8\lt x$.
