Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.7 Complete the Square - 4.7 Exercises - Skill Practice - Page 288: 36



Work Step by Step

The area of a parallelogram is the product of the base and its corresponding height. Hence here: $x(x+6)=48\\x^2+6x-48=0\\(x+3)^2-3^2-48=0\\(x+3)^2=57\\x+3=\pm\sqrt{57}\\x=-3\pm\sqrt{57}$ But we know that $x$ is non-negative, thus $x=-3+\sqrt{57}$
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