Answer
The solutions are $x=1$ or $x=-5$.
Work Step by Step
$ x^{2}+4x+4=9\qquad$ ...write left side as a binomial squared.
$(x+2)^{2}=9\qquad$ ...take square roots of each side.
$ x+2=\pm 3\qquad$ ...add $-2$ to each side.
$ x+2-2=\pm 3-2\qquad$ ...simplify.
$ x=-2\pm 3\qquad$ ...write as separate equations.
$x=-2+3$ or $ x=-2-3\qquad$ ...simplify.
$x=1$ or $x=-5$
