Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.7 Complete the Square - 4.7 Exercises - Mixed Review - Page 291: 79


The equation of the line is $y=3x-2$

Work Step by Step

$(x_{1},y_{1})=(-1,-5)$ $(x_{2},y_{2})=(1,1)$ Find the slope of the line: $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ $m=\displaystyle \frac{1-(-5)}{1-(-1)}=\frac{6}{2}=3$ You know the slope and a point on the line, so use point-slope form with either given point to write an equation of the line. Choose $(x_{1},y_{1})=(-1,-5).$ $ y-y_{1}=m(x-x_{1})\qquad$ ...substitute $-5$ for $y_{1},\ 3$ for $m$ and $-1$ for $x_{1}$. $y-(-5)=3(x-(-1))$ $ y+5=3(x+1)\qquad$ ...apply the Distributive Property. $ y+5=3x+3\qquad$ ...add $-5$ to each side. $y=3x-2$
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