# Chapter 4 Quadratic Functions and Factoring - 4.7 Complete the Square - 4.7 Exercises - Mixed Review - Page 291: 72

$b^{2}-4ac=76$

#### Work Step by Step

$a=3,b=2,c=-6$ $b^{2}-4ac\qquad$ ...substitute $3$ for $a,\ 2$ for $b$ and $-6$ for $c$. $=(2)^{2}-4\cdot 3\cdot(-6)\qquad$ ...evaluate $(2)^{2}$ $=4-4\cdot 3\cdot(-6)\qquad$ ...multiply before subtracting $=4+72$ $=76$

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