Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - 4.5 Exercises - Skill Practice - Page 270: 29

Answer

The solutions are $10 $ and $-10.$

Work Step by Step

$\displaystyle \frac{x^{2}}{25}-6=-2\qquad$ ...multiply each side with $25$. $ x^{2}-150=-50\qquad$ ...add $150$ to each side. $ x^{2}-150+150=-50+150\qquad$ ...simplify $ x^{2}=100\qquad$ ...take square roots of each side. $\sqrt{x^{2}}=\sqrt{100}\qquad$ ...simplify. ...When solving an equation of the form $x^{2}=s$ where $s>0$, we find both the positive and negative solutions. $x=\pm 10$
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