Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - 4.5 Exercises - Skill Practice - Page 270: 26


The solutions are $4\sqrt{7} $ and $-4\sqrt{7}$

Work Step by Step

$ 4p^{2}=448\qquad$ ...divide each side with $4$ $ p^{2}=112\qquad$ ...take square roots of each side. $\sqrt{p^{2}}=\sqrt{112}\qquad$ ...simplify ...When solving an equation of the form $x^{2}=s$ where $s>0$, we find both the positive and negative solutions. $ p=\pm\sqrt{112}\qquad$ ...rewrite $112$ as a product of two factors so that one factor is a perfect square. ($112=16\cdot 7$) $ p=\pm\sqrt{16\cdot 7}\qquad$ ...use the Product Property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ $ p=\pm\sqrt{16}\cdot\sqrt{7}\qquad$ ...evaluate $\sqrt{16} $ ($\sqrt{16}=4$) $p=\pm 4\sqrt{7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.