Answer
$$\frac{6+3\sqrt{10}+2\sqrt{7}+\sqrt{70}}{6}$$
Work Step by Step
Simplifying the expression using the rules of radicals, we find:
$$\frac{\left(3+\sqrt{7}\right)\left(2+\sqrt{10}\right)}{\left(2-\sqrt{10}\right)\left(2+\sqrt{10}\right)} \\ \frac{\left(3+\sqrt{7}\right)\left(2+\sqrt{10}\right)}{6} \\ \frac{6+3\sqrt{10}+2\sqrt{7}+\sqrt{70}}{6}$$
