Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.5 Solve Quadratic Equations by Finding Square Roots - 4.5 Exercises - Skill Practice - Page 269: 11


$\displaystyle \frac{8}{\sqrt{3}}=\frac{8\sqrt{3}}{3}$

Work Step by Step

$\displaystyle \frac{8}{\sqrt{3}}\qquad$ ...rationalize the denominator by multyplying both the numerator and the denominator with $\sqrt{3}$. $=\displaystyle \frac{8\cdot\sqrt{3}}{\sqrt{3}\cdot\sqrt{3}}\qquad$ ...apply the Product Property $\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}$ in the denominator. $=\displaystyle \frac{8\sqrt{3}}{\sqrt{3\cdot 3}}\qquad$ ...simplify $=\displaystyle \frac{8\sqrt{3}}{\sqrt{9}}\qquad$ ...evaluate the denominator ($\sqrt{9}=3$) $=\displaystyle \frac{8\sqrt{3}}{3}$
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