## Algebra 2 (1st Edition)

$x=6$.
Our equation is, according to the text of the exercise: $2\cdot24\cdot10=(24+x)(10+x)\\480=240+x^2+34x\\x^2+34x-240=0\\(x-6)(x+40)=0$ Thus $x=6$ or $x=-40$ but $x$ has to be positive, thus $x=6$.