Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.3 Solve x(squared) + bx + c = 0 - 4.3 Exercises - Skill Practice - Page 256: 52

Answer

-3, 15

Work Step by Step

Since the coefficient of the squared term is one, we know that the expression must factor to: $$ (x\pm a)(x\pm b)$$ Here, we see that a and b must multiply to get $-45$ and add to get $-12$. Thus, we find that the solution is: $$(x-15)(x+3)$$ Thus, setting each factor equal to zero, we find that the solutions are: $$-3, 15$$
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