Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 4 Quadratic Functions and Factoring - 4.2 Graph Quadratic Functions in Vertex or Intercept Form - 4.2 Exercises - Problem Solving - Page 251: 54

Answer

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Work Step by Step

The function is in the form $a(x-h)^2+k$. We know that the axis of symmetry is $\frac{p+q}{2}$. The first function is $y=- 0.5(x - 6)+ 18$ where $a=-0.5\\h=6\\k=18$ The vertex of this function is $(h,k)=(6,18)$ The second function is $y=- 1.17(x - 6)+ 42$ where $a=-1.17\\h=6\\k=42$ The vertex of this function is $(h,k)=(6,42)$ Hence, the maximum value of the first function is $y=18$. The maximum value of the second function is $y=42$. Since $y=k$ is the maximum value of the function, $k$ affects the maximum heights of the jumps on the two pogo sticks. Other constants ($a$ and $h$) do not affect the maximum heights of the jumps.
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